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An organic compound (A) has the molecular formula C8H9Br and on warming with alcoholic AgNO3 it produces a yellow precipitate. When (A) is oxidized, it yields an acid (B) with formula C8H6O4. Acid (B) readily cyclizes to its anhydride on heating. Which of the following is compound (A)?
- m-CH3C6H4CH2Br
- o-BrC6H4C2H5
- p-CH3C6H4CH2Br
- o-CH3C6H4CH2Br
Correct answer: o-CH3C6H4CH2Br
Solution
A gives AgBr (benzylic C-H2Br) with alcoholic AgNO3; oxidation of both the CH3 and CH2Br groups of o-CH3C6H4CH2Br gives o-phthalic acid C8H6O4, which readily forms phthalic anhydride on heating. A para isomer would give terephthalic acid, which does not cyclize.
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