On monochlorination of 2-methylbutane, how many chiral compounds can be formed?
8
2
4
6
Correct answer: 4
Solution
Monochlorination of 2-methylbutane gives 1-chloro-2-methylbutane and 2-chloro-3-methylbutane as the only products with a stereocentre. Each exists as a pair of enantiomers, so the number of chiral compounds formed is 2 x 2 = 4.