Correct answer: 7.6
The decomposition of PbSO4 in a lead-acid battery involves the transfer of 2 moles of electrons per mole of PbSO4. Since 0.05 Faraday corresponds to 0.05 moles of electrons, this means 0.025 moles of PbSO4 are decomposed. Multiplying 0.025 moles by the molar mass of PbSO4 (303 g/mol) gives approximately 7.6 grams.