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A 0.2 M solution of an electrolyte has a resistance of 50 Ω. Its specific conductance is 1.3 S m⁻¹. For a 0.4 M solution of the same electrolyte, the resistance is 260 Ω. The molar conductivity of this solution is

1. 6.25 × 10⁻⁴ S m² mol⁻¹
2. 625 × 10⁻⁴ S m² mol⁻¹
3. 62.5 S m² mol⁻¹
4. 6250 S m² mol⁻¹

Correct answer: 6.25 × 10⁻⁴ S m² mol⁻¹

Solution

Cell constant = kappa x R = 1.3 x 50 = 65 m^-1. For 0.4 M: kappa = 65/260 = 0.25 S m^-1. With c = 400 mol m^-3, Lambda_m = kappa/c = 0.25/400 = 6.25e-4 S m^2 mol^-1.

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