Correct answer: 128 S cm² mol−1
The limiting molar conductivity of NaBr can be estimated using the known values of the limiting molar conductivities of NaCl and KBr, applying the principle of additivity for strong electrolytes. By calculating the difference between the conductivities of KBr and KCl and adjusting for the contribution of Na+, we arrive at the value of 128 S cm² mol⁻¹ for NaBr.