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Solubility product of silver bromide is 5.0 × 10⁻¹³. The quantity of potassium bromide (molar mass taken as 120 g mol⁻¹) to be added to 1 litre of 0.05 M solution of silver nitrate to start the precipitation of AgBr is
- 1.2 × 10⁻¹⁰ g
- 1.2 × 10⁻⁹ g
- 6.2 × 10⁻⁵ g
- 5.0 × 10⁻⁸ g
Correct answer: 1.2 × 10⁻⁹ g
Solution
The correct option is derived from the solubility product expression, where the concentration of bromide ions must reach a level that exceeds the solubility product of silver bromide (AgBr) to initiate precipitation. By calculating the required concentration of bromide ions and converting it to mass using the molar mass of potassium bromide, we find that 1.2 × 10⁻⁹ g is the precise amount needed to start the precipitation.
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