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ExamsJEE MainChemistry

The solubility product of a salt having general formula MX2, in water, is 4 × 10⁻¹². The concentration of M2+ ions in the aqueous solution of the salt is

  1. 4.0 × 10⁻¹⁰ M
  2. 1.6 × 10⁻⁴ M
  3. 1.0 × 10⁻⁴ M
  4. 2.0 × 10⁻⁶ M

Correct answer: 1.0 × 10⁻⁴ M

Solution

The solubility product (Ksp) expression for the salt MX2 is Ksp = [M2+][X-]². Given Ksp = 4 × 10⁻¹², if we let the solubility of MX2 be 's', then [M2+] = s and [X-] = 2s. Substituting these into the Ksp expression gives 4 × 10⁻¹² = s(2s)² = 4s³, leading to s = 1.0 × 10⁻⁴ M for [M2+].

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