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At temperature T, the equilibrium constant for N2(g) + O2(g) ⇌ 2NO(g) is 4 × 10⁻⁴. What is the value of Kc for the reaction NO(g) ⇌ 1/2 N2(g) + 1/2 O2(g) at the same temperature?

1. 4 × 10⁻⁴
2. 50
3. 2.5 × 10²
4. 0.02

Correct answer: 50

Solution

The equilibrium constant for the reverse reaction is the reciprocal of the original reaction's equilibrium constant. Since the new reaction involves taking the square root of the original reaction's equilibrium constant (because of the coefficients being halved), we find that Kc = 1 / (4 × 10⁻⁴)^(1/2) = 50.

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