Exams › JEE Main › Chemistry
A piston filled with 0.04 mol of an ideal gas expands reversibly from 50.0 mL to 375 mL at a constant temperature of 37.0°C. As it does so, it absorbs 208 J of heat. The values of q and w for the process will be: (R = 8.314 J/mol K) [ln 7.5 = 2.01]
- q = +208 J, w = −208 J
- q = −208 J, w = −208 J
- q = −208 J, w = +208 J
- q = +208 J, w = +208 J
Correct answer: q = +208 J, w = −208 J
Solution
Heat absorbed q = +208 J. For an isothermal process of an ideal gas dU = 0, so w = -q = -208 J. Thus q = +208 J, w = -208 J.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →