Exams › JEE Main › Chemistry
An ideal gas expands in volume from 1 × 10⁻³ to 1 × 10⁻² m³ at 300 K against a constant pressure of 1 × 10⁵ N m⁻². The work done is
- 270 kJ
- −900 kJ
- −900 J
- 900 J
Correct answer: −900 J
Solution
Work done on the gas during expansion against constant external pressure = -P_ext*Delta_V = -(1e5)(1e-2 - 1e-3) = -900 J.
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