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Which expression correctly relates the Gibbs free energy change for a reaction to its equilibrium constant Kc?
- −ΔG = RT ln Kc
- ΔG° = RT ln Kc
- −ΔG° = RT ln Kc
- ΔG = RT ln Kc
Correct answer: −ΔG° = RT ln Kc
Solution
The correct thermodynamic relation uses the standard free energy: delta G(standard) = -RT ln Kc, equivalently -delta G(standard) = RT ln Kc.
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