Exams › JEE Main › Chemistry
An amino acid has a carboxyl group with pKₐ1 = 2.34 and an ammonium group with pKₐ2 = 9.60. At what pH will this amino acid have its isoelectric point?
- 5.97
- 2.34
- 9.60
- 6.97
Correct answer: 5.97
Solution
For a neutral amino acid the isoelectric point is the mean of the two relevant pKa values: pI = (2.34 + 9.60)/2 = 5.97.
Related JEE Main Chemistry questions
⚔️ Practice JEE Main Chemistry free + battle 1v1 →