Exams › JEE Main › Chemistry

When aniline (C6H5NH2) is treated with carbon disulphide in the presence of HgCl2 and heat, which product is formed?

1. phenyl isocyanide
2. phenyl cyanide
3. p-aminobenzenesulphonic acid
4. phenyl isothiocyanate

Correct answer: phenyl isothiocyanate

Solution

Heating aniline with carbon disulphide gives a dithiocarbamic acid intermediate, which is desulphurised by HgCl2 to form phenyl isothiocyanate (C6H5-N=C=S) - the Hofmann mustard-oil reaction.

Related JEE Main Chemistry questions

• Lactic acid loses its optical activity when the hydroxyl group is replaced by hydrogen because
• Which is the most suitable technique for separating a mixture of sugars?
• Which statement correctly compares the staggered and eclipsed conformations of ethane?
• Which statement correctly describes a common feature shared by optical and geometrical isomerism?
• Which substituent lowers the reactivity of a benzene ring toward electrophilic substitution, yet still mainly directs a new group to the ortho and para positions?
• Among the following substances, which has the greatest affinity for a proton?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →