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In the reaction sequence CH3CH2Cl a0--NaCN--> X a0--Ni/H2--> Y a0--acetic anhydride--> Z, what is the compound Z?
- CH3CH2CH2NHCOCH3
- CH3CH2CH2NH2
- CH3CH2CH2CONHCH3
- CH3CH2CH2CONHCOCH3
Correct answer: CH3CH2CH2NHCOCH3
Solution
CH3CH2Cl + NaCN -> CH3CH2CN (X). Ni/H2 reduces the nitrile to the primary amine CH3CH2CH2NH2 (Y). Acetic anhydride acetylates this amine to give CH3CH2CH2NHCOCH3 (Z, N-propylacetamide).
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