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When silver benzoate is treated with bromine, the product obtained is

1. benzene
2. benzoyl hypobromite (COOBr)
3. bromobenzene containing a COOAg group
4. C6H5Br

Correct answer: C6H5Br

Solution

Silver benzoate with bromine undergoes the Hunsdiecker reaction: C6H5COOAg + Br2 -> C6H5Br + CO2 + AgBr. The product is bromobenzene, C6H5Br.

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