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A hydrogen electrode is prepared by immersing a platinum wire in an HCl solution of pH 10 and bubbling hydrogen gas over the platinum at a pressure of 1 atm. What is the oxidation potential of this electrode?
- 0.59 V
- 0.118 V
- 1.18 V
- 0.059 V
Correct answer: 0.59 V
Solution
For 2H+ + 2e- -> H2, E_red = -(0.059/2)*log(1/[H+]^2) = -0.059*pH = -0.59 V at pH 10. Oxidation potential = -E_red = +0.59 V.
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