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A conductivity cell is filled with 0.1 M KCl solution having conductivity X Ω⁻¹ cm⁻¹, and its conductance is Y Ω⁻¹. When the same cell is filled with 0.1 M NaOH solution, the conductance becomes Z Ω⁻¹. The molar conductance of NaOH is

1. 10 XZ / Y
2. 10⁴ XZ / Y
3. 10⁴ XZ / (Y)
4. XZ / Y

Correct answer: 10⁴ XZ / Y

Solution

Cell constant G* = kappa/conductance = X/Y. For NaOH, kappa_NaOH = G* * Z = XZ/Y. Molar conductance = kappa*1000/C = (XZ/Y)*1000/0.1 = 10^4 * XZ/Y.

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