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An electrolytic cell is filled with aqueous Ag2SO4 and fitted with platinum electrodes. Electrolysis is continued until 1.6 g of O2 is evolved at the anode. How much silver will be deposited at the cathode?

1. 107.88 g
2. 1.6 g
3. 0.8 g
4. 21.60 g

Correct answer: 21.60 g

Solution

1.6 g O2 = 0.05 mol = 0.2 mol electrons (O2 needs 4e-). Ag+ + e- -> Ag, so 0.2 mol Ag deposit = 0.2 x 107.88 = 21.6 g.

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