Exams › JEE Main › Chemistry

In a cesium chloride crystal, the separation between neighboring ions is

1. a
2. a/2
3. √3a/2
4. 2a/√3

Correct answer: √3a/2

Solution

In CsCl the cation and anion touch along the body diagonal, so the nearest-neighbour separation is sqrt3 a/2, not 2a/sqrt3.

Related JEE Main Chemistry questions

• Glass is classified as a
• In the wurtzite crystal lattice, what are the coordination numbers of Zn2+ and S2- respectively?
• In KBr, the coordination number of each ion changes from X to Y when the crystal is subjected to which condition?
• How many carbon atoms are present in one unit cell of the diamond crystal structure?
• A sodium chloride crystal has a pycnometric density of 2.165 × 10³ kg m⁻³ and an X-ray density of 2.178 × 10³ kg m⁻³. What fraction of lattice sites are vacant in the crystal?
• Which set of unit-cell parameters represents a cubic lattice, if the edge lengths are a, b, c and the interaxial angles are α, β, and γ?

⚔️ Practice JEE Main Chemistry free + battle 1v1 →