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An organic compound sample weighing 0.32 g gives 0.233 g of BaSO₄ on analysis. Taking atomic masses Ba = 137 and S = 32, what is the percentage of sulphur in the compound?

1. 1.0
2. 10.0
3. 23.5
4. 32.1

Correct answer: 10.0

Solution

S = 0.233 x 32/233 = 0.032 g; %S = 0.032/0.32 x 100 = 10.0%. The stored 1.0% is off by a factor of ten.

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