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A saturated solution of the sparingly soluble strong electrolyte AgIO₃ (molar mass = 283) is in equilibrium as AgIO₃(s) ⇌ Ag⁺(aq) + IO₃⁻(aq). If the solubility product constant, Ksp, of AgIO₃ at the stated temperature is 1.0 × 10⁻⁸, what mass of AgIO₃ is present in 100 mL of this saturated solution?
- 1.0 × 10⁻⁴ g
- 2.83 × 10⁻² g
- 2.83 × 10⁻³ g
- 1.0 × 10⁻⁷ g
Correct answer: 2.83 × 10⁻³ g
Solution
To find the mass of AgIO₃ in a saturated solution, we first determine the molarity of Ag⁺ and IO₃⁻ ions using the Ksp value. Given Ksp = [Ag⁺][IO₃⁻] = 1.0 × 10⁻⁸, and since the concentrations of Ag⁺ and IO₃⁻ are equal in a saturated solution, we can set both to 's'. Thus, s² = 1.0 × 10⁻⁸, leading to s = 1.0 × 10⁻⁴ M. In 100 mL, this corresponds to 1.0 × 10⁻⁴ moles, which converts to mass using the molar mass of AgIO₃ (283 g/mol), resulting in 2.83 × 10⁻³ g.
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