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Choose the sequence that arranges the following species in increasing order of size:

1. Ca2+ < K+ < Ar < Cl− < S2−
2. Ar < Ca2+ < K+ < Cl− < S2−
3. Ca2+ < Ar < K+ < Cl− < S2−
4. Ca2+ < K+ < Ar < S2− < Cl−

Correct answer: Ca2+ < K+ < Ar < Cl− < S2−

Solution

The correct option arranges the species based on their ionic or atomic radii, with cations being smaller than their neutral atoms and anions being larger. Ca2+ is the smallest due to losing two electrons, followed by K+, then neutral Ar, and finally Cl− and S2−, which are larger due to gaining electrons.

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