StreakPeaked· Practice

ExamsJEE MainChemistry

The bond dissociation energy for one mole of Cl–Cl bonds in Cl₂ is 242 kJ mol⁻¹. What is the maximum wavelength of radiation that can just rupture one Cl–Cl bond? (Take c = 3 × 10⁸ m s⁻¹ and Nₐ = 6.02 × 10²³ mol⁻¹.)

  1. 594 nm
  2. 640 nm
  3. 700 nm
  4. 494 nm

Correct answer: 494 nm

Solution

Per-bond energy = 242000/6.02e23 = 4.02e-19 J; lambda = (6.626e-34 x 3e8)/4.02e-19 = 4.94e-7 m = 494 nm. The stored 594 nm is wrong.

Related JEE Main Chemistry questions

⚔️ Practice JEE Main Chemistry free + battle 1v1 →