When 100 mL of a 20.8% BaCl₂ solution is mixed with 50 mL of a 9.8% H₂SO₄ solution, the mass of BaSO₄ produced will be: (Ba = 137, Cl = 35.5, S = 32, H = 1, O = 16)

Question

Accepted Answer

11.65 g. BaCl2 = 20.8 g/208 = 0.1 mol; H2SO4 = 4.9 g/98 = 0.05 mol (limiting). BaSO4 = 0.05 x 233 = 11.65 g. Stored 30.6 g is wrong.

When 100 mL of a 20.8% BaCl₂ solution is mixed with 50 mL of a 9.8% H₂SO₄ solution, the mass of BaSO₄ produced will be: (Ba = 137, Cl = 35.5, S = 32, H = 1, O = 16)

Solution

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