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ExamsJEE AdvancedPhysics

A capillary tube of radius r = 0.2 mm is dipped vertically into a liquid of density rho = 1 g/cc. A small piston (x) inserted into the capillary maintains a constant air pressure P1 = 2*10⁴ dynes/cm² on the hemispherical meniscus. The ambient pressure is P0 = 10⁵ dynes/cm² and the surface tension of the liquid is T = 72 dynes/cm. Ignoring the weight of the curved part of the liquid, find the rise (or fall) h of the liquid column in cm.

  1. h = 4.6 cm (liquid is depressed below the outside level)
  2. h = 4.6 cm (liquid rises above the outside level)
  3. h = 2.3 cm (liquid rises)
  4. h = 8.2 cm (liquid depressed)

Correct answer: h = 4.6 cm (liquid is depressed below the outside level)

Solution

The piston applies P1 above the meniscus. The pressure jump across the meniscus is 2T/r. Setting up the hydrostatic balance between the pressure inside the tube at the level of the outside free surface and the ambient pressure P0 gives the column height h. Since P1 + 2T/r exceeds P0, the liquid inside is pushed down (depressed).

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