Exams › JEE Advanced › Physics
Two large thin conducting plates are placed close together (small gap) in a uniform external electric field E that is perpendicular to the plates. Each plate has area A; charges +Q and -Q are placed on them. Considering points R, S and T (R outside near the +Q plate, S between the plates, T outside near the -Q plate as shown), which statement about the field is correct?
- field at point R is E
- field at point S is E
- field at point T is (E + Q/(epsilon₀*A))
- field at point S is (E + Q/(A*epsilon₀))
Correct answer: field at point R is E
Solution
The two oppositely charged plates form a capacitor-like configuration: their combined field is zero in the outside regions (points R and T) and is Q/(epsilon₀*A) in the gap (point S), pointing from +Q to -Q. Superposing the external field E: at R (outside) the net field is just E (plates contribute zero). At S (inside) the net field is E + Q/(epsilon₀*A) only if the plate field aligns with E. The clean, unambiguously correct statement is that the field at R equals E.
Related JEE Advanced Physics questions
- A particle with charge -q and mass m revolves in a circular path of radius r around an infinitely long charged wire with linear charge density +λ. What is the time period of its motion?
- What is the value of the electrostatic potential at point H?
- The electric potential V varies with distance x from a fixed point as follows: V = 5 V for 0 <= x < 10 m, then V decreases linearly from 5 V at x = 10 m to -10 V at x = 20 m. The electric field at x = 13 m is:
- Two capacitors are connected in a circuit with two batteries and a switch S. The system is in steady state with S open. When S is closed, which of the following statements correctly describes the energy exchange?
- In a capacitor bridge circuit, four capacitors C1, C2, C3, and C4 are connected in a bridge configuration with an EMF source E. Capacitor C1 is in the top-left arm, C2 in the top-right arm, C3 in the bottom-left arm, and C4 in the bottom-right arm. Points P and Q are the mid-points (junctions). Find the potential difference V_P - V_Q.
- An isolated charged spherical soap bubble of radius r has the pressure inside equal to atmospheric pressure outside. The surface tension of the soap solution is T. If the total charge on the bubble can be written as N*pi*r*sqrt(2*T/epsilon0), find the integer value of N.
⚔️ Practice JEE Advanced Physics free + battle 1v1 →