StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A characteristic length l is built from the permittivity (epsilon) of a dielectric, the Boltzmann constant kB, the absolute temperature T, the number density n of charged particles (number per unit volume), and the charge q on each particle. Which of the following expressions for l is dimensionally correct?

  1. l = sqrt(epsilon*kB*T/(n*q²))
  2. l = sqrt(n*q²/(epsilon*kB*T))
  3. l = sqrt(q²/(epsilon*n^(2/3)*kB*T))
  4. l = sqrt(q²/(epsilon*n^(1/3)*kB*T))

Correct answer: l = sqrt(epsilon*kB*T/(n*q²))

Solution

From Coulomb energy, q²/(epsilon) has dimensions of (energy * length). So epsilon*kB*T/q² has dimensions of (energy)/(energy*length per...) -> work it out: epsilon*kB*T/q² has dimension 1/length, and dividing by n (1/length³) gives length². The square root is a length. This is the Debye screening length, l = sqrt(epsilon kB T/(n q²)).

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →