Exams › JEE Advanced › Physics
A configuration of point charges has potential energy U1. A charge q is brought into the configuration without moving any of the existing charges, raising the potential energy to U2. The electric potential at the location where q is placed (due to the original charges) is:
- (U2 - U1) / q
- (U1 - U2) / q
- (U1 + U2) / (2q)
- (U2 - U1) / (2q)
Correct answer: (U2 - U1) / q
Solution
Adding charge q to a point of potential V increases the system energy by q*V. Hence V = (U2 - U1)/q.
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