A displacement current of 4.425 microA flows in the gap of a parallel-plate capacitor when the applied voltage changes at the rate 10⁶ V/s. Each plate has area 40 cm² and the plate separation is x x 10⁻³ m. Taking e0 = 8.85 x 10⁻¹² C² N⁻¹ m⁻², find x.

Question

Accepted Answer

0.8. I_d = (e0 A/d)(dV/dt). Solving for d: d = e0 A (dV/dt)/I_d = (8.85x10⁻¹²)(40x10⁻⁴)(10⁶)/(4.425x10⁻⁶) = (8.85x10⁻¹² * 4x10⁻³ * 10⁶)/(4.425x10⁻⁶) = (3.54x10⁻⁸)/(4.425x10⁻⁶) = 0.8x10⁻³ m. So x = 0.8.

A displacement current of 4.425 microA flows in the gap of a parallel-plate capacitor when the applied voltage changes at the rate 10⁶ V/s. Each plate has area 40 cm² and the plate separation is x x 10⁻³ m. Taking e0 = 8.85 x 10⁻¹² C² N⁻¹ m⁻², find x.

Solution

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