In a series R-L-C circuit, the source frequency is half the resonant frequency. The circuit then behaves as:

capacitive
inductive
purely resistive
data insufficient

Correct answer: capacitive

Solution

At resonance X_L = X_C. Below resonance (here at half the resonant frequency) X_L decreases and X_C increases, so X_C > X_L and the circuit's net reactance is capacitive.

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