Exams › JEE Advanced › Physics
An electric field E = 30x² i (in SI units, with x in metres) exists in a region. Determine the potential difference V0 - VA, where V0 is the potential at the origin and VA is the potential at x = 2 m.
- -80 V
- 80 V
- 120 V
- -120 V
Correct answer: 80 V
Solution
The potential difference V0 - VA = -(VA - V0) = -[-integral from 0 to 2 of E dx] = integral from 0 to 2 of 30x² dx = 30*(x³/3) from 0 to 2 = 10*(8) = 80. So V0 - VA = 80 V (the units, though written as J, are volts).
Related JEE Advanced Physics questions
- A particle with charge -q and mass m revolves in a circular path of radius r around an infinitely long charged wire with linear charge density +λ. What is the time period of its motion?
- What is the value of the electrostatic potential at point H?
- The electric potential V varies with distance x from a fixed point as follows: V = 5 V for 0 <= x < 10 m, then V decreases linearly from 5 V at x = 10 m to -10 V at x = 20 m. The electric field at x = 13 m is:
- Two capacitors are connected in a circuit with two batteries and a switch S. The system is in steady state with S open. When S is closed, which of the following statements correctly describes the energy exchange?
- In a capacitor bridge circuit, four capacitors C1, C2, C3, and C4 are connected in a bridge configuration with an EMF source E. Capacitor C1 is in the top-left arm, C2 in the top-right arm, C3 in the bottom-left arm, and C4 in the bottom-right arm. Points P and Q are the mid-points (junctions). Find the potential difference V_P - V_Q.
- An isolated charged spherical soap bubble of radius r has the pressure inside equal to atmospheric pressure outside. The surface tension of the soap solution is T. If the total charge on the bubble can be written as N*pi*r*sqrt(2*T/epsilon0), find the integer value of N.
⚔️ Practice JEE Advanced Physics free + battle 1v1 →