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Correct answer: 0.13 A, directed from Q to P
This is a two-loop network where the 1 ohm resistor sits in the middle branch shared by both loops. Using Kirchhoff's rules, the unbalanced emf drives a small current through the central branch. Solving the loop equations gives a current of magnitude 0.13 A, and the sign of the result shows it flows from node Q to node P. The small value (not 1.3 A) and the non-zero result (not a balanced/zero case) confirm option 1.