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A potential difference of 5 V is maintained across a wire of length 0.1 m, producing a drift speed of 2.5 * 10⁻⁴ m/s for the conduction electrons. Given the free-electron density is 8 * 10²⁸ m⁻³, the resistivity of the wire material is approximately:
- 1.6 * 10⁻⁶ Ohm m
- 1.6 * 10⁻⁵ Ohm m
- 1.6 * 10⁻⁸ Ohm m
- 1.6 * 10⁻⁷ Ohm m
Correct answer: 1.6 * 10⁻⁵ Ohm m
Solution
Using E = V/L and j = n*e*v_d, resistivity rho = E/j gives about 1.6 * 10⁻⁵ Ohm m.
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