StreakPeaked· Practice

ExamsJEE AdvancedPhysics

A steel wire of length 10 cm is to be kept at constant length while its temperature is raised by 100 deg C. Find the pressure (stress) that must be applied to its ends. Take Young's modulus Y = 2*10¹¹ N m⁻² and coefficient of linear thermal expansion alpha = 1.1*10⁻⁵ K⁻¹.

  1. 2.2 * 10⁷ Pa
  2. 2.2 * 10⁶ Pa
  3. 2.2 * 10⁸ Pa
  4. 2.2 * 10⁹ Pa

Correct answer: 2.2 * 10⁸ Pa

Solution

The stress required equals Y*alpha*delta T = 2e11 * 1.1e-5 * 100 = 2.2e8 Pa, independent of length.

Related JEE Advanced Physics questions

⚔️ Practice JEE Advanced Physics free + battle 1v1 →