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The gap between two concentric conducting spheres of radii a and b (with b > a) is filled with a material of resistivity rho. Find the electrical resistance measured between the inner and outer spheres.
- rho/(4*pi) * (1/a - 1/b)
- rho/(2*pi) * (1/a - 1/b)
- rho/(2*pi) * (1/a + 1/b)
- rho/(4*pi) * (1/a + 1/b)
Correct answer: rho/(4*pi) * (1/a - 1/b)
Solution
Summing radial shell resistances gives R = (rho/4pi)(1/a - 1/b), since the cross-sectional area at radius r is 4*pi*r².
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