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Determine the volume density of elastic deformation energy in fresh water at a depth of h = 1000 m. (Compressibility of water = 0.49 GPa⁻¹; use P = rho*g*h.)
- 24.5 kJ/m³
- 47 kJ/m³
- 11.25 kJ/m³
- None of these
Correct answer: 24.5 kJ/m³
Solution
With P = rho g h about 9.8*10⁶ Pa, the elastic energy density u = (1/2) beta P² works out to about 24.5 kJ/m³.
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