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A rigid, thermally insulated container holds a coil of resistance 100 ohm carrying a steady current of 1 A. What is the change in internal energy of the system after 5 minutes?

30 kJ
zero
10 kJ
20 kJ

Correct answer: 30 kJ

Solution

All the Joule heat I² R t is retained (insulated, rigid), so dU = I² R t = 1*100*300 = 30000 J = 30 kJ.

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