Exams › JEE Advanced › Physics
A battery of emf E and internal resistance r is being charged: the battery's positive terminal is joined to charger terminal A and its negative terminal to charger terminal B. Which statement is correct?
- The potential difference between A and B must be greater than E.
- A must be at lower potential than B.
- Inside the battery, current flows from the positive terminal to the negative terminal.
- No current flows through the battery.
Correct answer: The potential difference between A and B must be greater than E.
Solution
To drive charging current into the battery, the charger's terminal voltage must overcome both the emf and the internal-resistance drop, so V_AB = E + I*r > E.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →