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A 1 kg ball falls vertically and strikes the floor at 25 m/s, then bounces back up with a speed of 10 m/s. What is the impulse delivered to the ball during the contact?

1. 35 kg m/s downwards
2. 35 kg m/s upwards
3. 30 kg m/s downwards
4. 30 kg m/s upwards

Correct answer: 35 kg m/s upwards

Solution

Taking up as positive, impulse = 1*(10 - (-25)) = 35 kg m/s, directed upward.

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