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A particle's angular displacement is theta = omega0 * t + (1/2) * alpha * t², where omega0 = 1 rad/s and alpha = 1.5 rad/s². Determine its angular velocity at t = 2 s.
- 2 rad/s
- 3 rad/s
- 4 rad/s
- 5 rad/s
Correct answer: 4 rad/s
Solution
Differentiating theta gives omega = omega0 + alpha*t = 1 + 1.5*2 = 4 rad/s.
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