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In a series LCR circuit the resistance is R = 20 ohm and the inductive reactance is X_L = 200 ohm. After how many complete oscillations does the ratio of instantaneous current to its maximum value fall to 1/e?
- 10
- 10/pi
- 100
- 100/pi
Correct answer: 10/pi
Solution
The damping condition e^(-Rt/2L) = 1/e gives t = 2L/R. The number of oscillations n = t/T = (2L/R)*(omega/(2*pi)) = omega*L/(pi*R) = X_L/(pi*R) = 200/(20*pi) = 10/pi.
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