The radionuclide Carbon-11 (mass 11.011434 u) undergoes beta-plus (positron) emission to form Boron-11 (mass 11.009305 u). Given electron mass = 0.000548 u and 1 u = 931.5 MeV/c², find the Q-value of this decay.

0.962 MeV
0.962 × 10³ MeV
0.962 eV
Zero

Correct answer: 0.962 MeV

Solution

Q = [m(C-11) - m(B-11) - 2*mₑ] * 931.5 MeV = [11.011434 - 11.009305 - 2*0.000548] * 931.5 = [0.001033] * 931.5 ≈ 0.962 MeV.

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