Exams › JEE Advanced › Physics
A linearly polarized electromagnetic wave E_vec = E0 * i_hat * cos(k*z - omega*t) is incident normally on a perfectly reflecting infinite wall at z = 0. Assuming the wall is optically inactive, what is the expression for the reflected wave?
- E_r_vec = -E0 * i_hat * cos(k*z - omega*t)
- E_r_vec = E0 * i_hat * cos(k*z + omega*t)
- E_r_vec = -E0 * i_hat * cos(k*z + omega*t)
- E_r_vec = E0 * i_hat * sin(k*z - omega*t)
Correct answer: E_r_vec = -E0 * i_hat * cos(k*z + omega*t)
Solution
On reflection from a perfectly conducting surface, the electric field undergoes a phase shift of 180 deg (sign reversal). The reflected wave travels in the +z direction reversed to -z... wait: incident travels in +z, reflected travels in -z. The reflected wave: E_r = -E0*i_hat*cos(k*z + omega*t) (propagating in -z direction with pi phase shift).
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →