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ExamsJEE AdvancedPhysics

A linearly polarized electromagnetic wave E_vec = E0 * i_hat * cos(k*z - omega*t) is incident normally on a perfectly reflecting infinite wall at z = 0. Assuming the wall is optically inactive, what is the expression for the reflected wave?

  1. E_r_vec = -E0 * i_hat * cos(k*z - omega*t)
  2. E_r_vec = E0 * i_hat * cos(k*z + omega*t)
  3. E_r_vec = -E0 * i_hat * cos(k*z + omega*t)
  4. E_r_vec = E0 * i_hat * sin(k*z - omega*t)

Correct answer: E_r_vec = -E0 * i_hat * cos(k*z + omega*t)

Solution

On reflection from a perfectly conducting surface, the electric field undergoes a phase shift of 180 deg (sign reversal). The reflected wave travels in the +z direction reversed to -z... wait: incident travels in +z, reflected travels in -z. The reflected wave: E_r = -E0*i_hat*cos(k*z + omega*t) (propagating in -z direction with pi phase shift).

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