Exams › JEE Advanced › Physics
A resistor with an irregular (non-uniform) cross-section is connected across a constant potential difference source. At the narrower cross-section (point P) and wider cross-section (point Q), which of the following statements is correct?
- Mean kinetic energy of free electrons at P is greater than at Q.
- Rate of heat generation per unit length at P is greater than at Q.
- Rate of electrons crossing per unit area of cross-section at P is less than at Q.
- Electric field intensity at P is greater than that at Q.
Correct answer: Electric field intensity at P is greater than that at Q.
Solution
The electric field E = rho*J = rho*I/A is inversely proportional to cross-sectional area, so E is largest at P (narrowest). Mean KE of free electrons depends only on temperature (same throughout in steady state), not on drift velocity.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →