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Conductors A and B are two spherical shells of the same size. A is solid and B is hollow. Both are charged to the same electric potential. If the charge on A is QA and on B is QB, which relation is correct?
- QA is less then QB
- QA is greater than QB but not double
- QA = QB
- QA = 2QB
Correct answer: QA = QB
Solution
Since all charge on a conductor resides on the outer surface, a solid sphere and a hollow sphere of the same outer radius R are electrostatically equivalent. At equal potential V = kQ/R, with equal R, we must have QA = QB.
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