In a half-wave rectifier, the average (DC) output voltage over a full cycle is V. Using the same peak voltage, what is the RMS voltage in a full-wave rectifier?

pi*V/sqrt(2)
pi*V/2
pi*V/(2*sqrt(2))
sqrt(2)*pi*V

Correct answer: pi*V/sqrt(2)

Solution

For a half-wave rectifier, average output over full cycle = V_peak/pi. Given this equals V, V_peak = pi*V. For a full-wave rectifier with the same peak voltage, V_rms = V_peak/sqrt(2) = pi*V/sqrt(2).

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