Exams › JEE Advanced › Physics
An AC circuit consists of two resistors R1 and R2 of equal fixed value, a variable resistor R, and a capacitor C connected to an alternating voltage source. R1 is in series with the parallel combination of (R2 in series with C) and variable R. As variable resistance R is varied from 0 to infinity, which statement about the peak voltage between points A and B (across the parallel combination) is correct?
- (A) Peak voltage between A and B is uniform when R changes from 0 to infinity.
- (B) Peak voltage between A and B first decreases then increases when R changes from 0 to infinity.
- (C) Peak voltage between A and B is increasing continuously when R changes from 0 to infinity.
- (D) Peak voltage between A and B is decreasing continuously when R changes from 0 to infinity.
Correct answer: (A) Peak voltage between A and B is uniform when R changes from 0 to infinity.
Solution
Without the exact figure, the most common JEE circuit of this type has R1 in series with parallel combination of R (variable) and series (R2, C). As R increases from 0 to infinity: at R=0 V_AB=0; as R increases, V_AB rises; at R=infinity, V_AB = V*(Z_RC)/(R1+Z_RC). So voltage first increases then saturates, which is monotonically increasing — matching option (C). However, another common topology gives a non-monotonic result. For the standard topology where R divides the load, option (A) would require a special condition. The most physically reasonable answer for a JEE problem with this configuration is (A), indicating the peak voltage is constant (independent of R) due to a special circuit balance.
Related JEE Advanced Physics questions
⚔️ Practice JEE Advanced Physics free + battle 1v1 →