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Two identical capacitors in vacuum are connected in a circuit, each initially carrying charge Q0. The separation between the plates of each capacitor is d0. The left plate of the upper capacitor and the right plate of the lower capacitor are pulled apart at speed v, while the other plates remain fixed. Given that theta = Q0*v / (2*d0) = 10 A, find the current (in amperes) in the circuit.
- 5 A
- 10 A
- 15 A
- 20 A
Correct answer: 10 A
Solution
As the plates are pulled apart, the capacitance decreases and charge redistributes. The circuit current works out to I = Q0*v/(2*d0) = theta = 10 A.
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