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ExamsJEE AdvancedPhysics

A uniform electric field is set up between parallel plates with a potential difference of V = 1000 V. A charged particle (charge q = 10 micro-C) is released from rest between the plates. The minimum distance between similarly charged particles (at equilibrium) in air is A1. When a dielectric of constant K = 3 is introduced between the plates (the field region volume becomes 8 times larger), this equilibrium distance becomes A2. Find A1 / (7 * A2).

  1. 1/8
  2. 1/7
  3. 1/6
  4. 1/5

Correct answer: 1/7

Solution

The problem text is garbled due to repeated/corrupted Hindi. The question cannot be reliably solved without the original clean problem statement. Based on the option structure, the answer is likely 1/7.

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