Carbon-11 (atomic mass 11.011434 u) undergoes decay to Boron-11 (atomic mass 11.009305 u). Given: electron mass = 0.000549 u, 1 u = 930 MeV/c². Select the correct statements about this nuclear decay.

Beta-minus particle is emitted.
Beta-plus particle is emitted.
Maximum kinetic energy of the emitted particle is 0.959 MeV.
An anti-neutrino is also released in this nuclear reaction.

Correct answer: Beta-plus particle is emitted.

Solution

C-11 (Z=6) → B-11 (Z=5): Z decreases by 1, so it is beta-plus decay, emitting a positron and a neutrino (not anti-neutrino). Q = (11.011434 - 11.009305 - 2*0.000549)*930 = (0.002129 - 0.001098)*930 = 0.001031*930 ≈ 0.959 MeV. Statements B and C are correct.

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